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-3x^2-7x-14=-10
We move all terms to the left:
-3x^2-7x-14-(-10)=0
We add all the numbers together, and all the variables
-3x^2-7x-4=0
a = -3; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·(-3)·(-4)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*-3}=\frac{6}{-6} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*-3}=\frac{8}{-6} =-1+1/3 $
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